Question :-
- A Direct Current of 3.0 A flows through a Circuit consisting of a Battery and a 6.0 Ohm's Resistor. Calculate the Potential Difference across the Resistor .
Answer :-
- Potential Difference is 18 Volt's .
Explanation :-
As per the provided information in the given question, we have been given that the Current of the Device is 3.0 Ampere . The Resistance is given as 6.0 Ohm's . And, we have been asked to calculate the Potential Difference .
As we know ,
Where ,
- V denotes to Potential Difference
- I denotes to Current
- R denotes to Resistance
Therefore , by Substituting the given values in the above Formula :-
[tex] \sf {\dag \: \: \: Potential \: Difference \: = \: Current \: \times \: Resistance} [/tex]
[tex] \sf {\Longrightarrow \: \: \: \sf Potential \: Difference \: = \: 3.0 \: \times \: 6.0} [/tex]
[tex] \sf {\Longrightarrow \: \: \: \sf Potential \: Difference \: = \: 3 \: \times \: 6} [/tex]
[tex] \bf {\Longrightarrow \: \: \: \bf {Potential \: Difference \: = \: 18 \: }} [/tex]
Hence :-
- Potential Difference = 18 Volt's .
[tex] \underline {\rule {210pt}{4pt}} [/tex]
Additional Information :-
[tex] \Longrightarrow \: \: \: \sf {Voltage \: = \: Current \: \times \: Resistance} [/tex]
[tex]\Longrightarrow \: \: \: \sf {Current \: = \: \dfrac {Voltage}{Resistance} } [/tex]
[tex]\Longrightarrow \: \: \: \sf {Resistance \: = \: \dfrac {Voltage}{Current} } [/tex]
[tex] \underline {\rule {210pt}{4pt}} [/tex]
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