[tex]\boxed{\bold{x = 2, 3}}[/tex]
Stepwise Solving:
[tex]\rightarrow \sf x^2-5x + 6 = 0[/tex]
[tex]\sf use \ the \ formula : x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a} \ \ when \ ax^2 + bx + c = 0[/tex]
Identify the coefficients:
Solve for x:
[tex]\dashrightarrow \ \sf x=\dfrac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4 \ x \ 1 \ x \ 6}}{2 \ x \ 1}[/tex]
[tex]\dashrightarrow \ \sf x=\dfrac{\left5\right\pm \sqrt{\left25-24}}{2}[/tex]
[tex]\dashrightarrow \ \sf x=\dfrac{\left5\right\pm \sqrt{1}}{2}[/tex]
[tex]\dashrightarrow \ \sf x=\dfrac{\left5\right\pm1}{2}[/tex]
[tex]\dashrightarrow \ \sf x=\dfrac{\left5\right+ 1}{2} \ , \dfrac{\left5\right- 1}{2}[/tex]
[tex]\dashrightarrow \ \sf x=\dfrac{6}{2} \ , \ \dfrac{4}{2}[/tex]
[tex]\dashrightarrow \ \sf x= 3, \ 2[/tex]
