Please help!!!

Triangle ABC is similar to triangle PQR
AB = 4cm
PQ=12cm
RQ= 16.5 cm
AC = xcm
PR= ycm

(a) Calculate the length of BC


(b) Write down an expression for y in terms of x

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Please help Triangle ABC is similar to triangle PQR AB 4cm PQ12cm RQ 165 cm AC xcm PR ycm a Calculate the length of BC b Write down an expression for y in terms class=

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Answer:

5.5

3y = x

Step-by-step explanation:

→ Find the scale factor enlargement

12 ÷ 4 = 3

→ Divide 16.5 by 3

5.5

→ Write SF in terms of x and y

3y = x

The Length of BC is 5.5 cm and equation for y in terms of x is y = 3x

What are similarity in triangles?

Two triangles are similar if they have the same ratio of corresponding sides and equal pair of corresponding angles. If two or more figures have the same shape, but their sizes are different, then such objects are called similar figures.

According to question

Triangle ABC ≅ triangle PQR  

where,

AB = 4cm

PQ=12cm

RQ= 16.5 cm

AC = xcm

PR= ycm

According to the similarity rule

the same ratio of corresponding sides

therefore,

[tex]\frac{AB}{PQ} = \frac{BC}{QR} = \frac{AC}{PR} \\[/tex]

(a) Calculate the length of BC

[tex]\frac{AB}{PQ} = \frac{BC}{QR}[/tex]

⇒ [tex]\frac{4}{12} = \frac{BC}{16.5}[/tex]

⇒ [tex]\frac{1}{3} = \frac{BC}{16.5}[/tex]

⇒ BC = 5.5 cm

 (b) Write down an expression for y in terms of x

we know  ,  [tex]\frac{AB}{PQ} = \frac{AC}{PR} \\[/tex]

⇒ [tex]\frac{4}{12} = \frac{x}{y} \\[/tex]

⇒ [tex]\frac{1}{3} = \frac{x}{y} \\[/tex]

⇒ [tex]y=3x[/tex]

Hence, Length of BC is 5.5 cm and equation for y = 3x

To know more about similarity in triangles  here :

https://brainly.com/question/20502441

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