To find the solutions to the quadratic equations
⇒ factor the equation
[tex]x^2-2x = 8\\x^2-2x-8=0\\(x-4)(x+2) = 0[/tex]
Now to find the exact solutions, we have to set 'x - 4' and 'x + 2' equal to 0
[tex]x - 4 = 0\\x = 4\\\\x + 2 = 0\\x = -2[/tex]
Thus the solution to this problem is -2 and 4
Hope that helps!
Answer:
4 and - 2
Step-by-step explanation:
x² - 2x = 8
x² - 2x - 8 = 0
x² + 2x - 4x - 8 = 0
x ( x + 2 ) - 4 ( x + 2 ) = 0
( x + 2 ) ( x - 4 ) = 0
x + 2 = 0
x = - 2
x - 4 = 0
x = 4
The values of x are - 2 and 4.
