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The maximum grain yield for corn is achieved by planting at a density of 37,000 plants per
acre. A farmer wants to maximize the yield for the field represented on the coordinate grid.
Each unit on the coordinate grid represents one foot. How many corn plants, to the nearest
thousand, does the farmer need? (Hint: 1 acrt = 43,560 ft?)
у
500 fx
E
F
X
-500
0
500
G
-500
H
The farmer needs approximately
corn plants.

The maximum grain yield for corn is achieved by planting at a density of 37000 plants per acre A farmer wants to maximize the yield for the field represented on class=

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abidemiokin

According to the question, there are 37000 plants per hectare, the total corn plan required is 475,665.75 corn plants

Determining the area of a trapezium?

The trapezium is a 2 -dimensional plane shape with the area calculated as shown below:

The formula for calculating the area of a trapezoid is expressed as:

Area = 0.5(a + b)h

Given the following parameters

  • a = 500 ft
    b = 900ft
    height h = 800ft

Substitute the given parameters
Area = 1/2 (500 + 900) * 800
Area = 1/2 (1400) * 800
Area = 560000 square feet

Since 1 acre is equivalent to 43560 square feet, hence the total acre required is expressed as:

Total acre = 560000/43560
Total  acre = 12.856 acres

Convert the acres to total corn plant

Also since there are 37000 plants per hectare, the total corn plan required is 475,665.75 corn plants

Learn more on area of trapezoid here: https://brainly.com/question/1463152

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