One point charge +Q is placed at the center of a square, and a second point charge -Q is placed at the upper-left corner of the square. It is observed that an electrostatic force of magnitude 2.0 N acts on the positive charge at the center. Now a third charge -Q is placed at the lower-left corner of the square, as shown in the figure. What is the magnitude of the net force that acts on the center charge now? The figure shows one positive charge labeled + Q placed at the center of a square and two negative charges labeled -Q placed at the upper left and the bottom left corners of the square.
a) 0.0 N
b) 2.8 N
c) 5.3 N
d) 4.0 N

Respuesta :

Answer:

One should draw a diagram showing the placement of the charges.

When both charges of -Q are placed there will be no force in the vertical direction because of cancellation of forces.

A line from one corner of the square to the other makes an angle of 45 degrees,

2 cos 45 deg will be the force due to one charge.

2 * .707 = 1.41 N

So for both charges the force is (horizontal, vertical is zero)

2 * 1.41 = 2.82 N

b) is correct

The magnitude of the net force that acts on the center charge will be 2.82 N.Option B is correct.

what is the charge?

When the matter is put in an electromagnetic field, it has an electric charge, which causes it to experience a force. A positive or negative electric charge can exist.

Charges that are similar repel each other, whereas charges that are dissimilar attract each other. The term "neutral" refers to an item that has no net charge.

Case 1 ;

One point charge +Q is placed at the center of a square, and a second point charge -Q is placed at the upper-left corner of the square.

When both charges of -Q are placed there will be no force in the vertical direction because of the cancellation of forces.

A line from one corner of the square to the other makes an angle of 45 degrees,

The force due to the one charge at the angle of the 45° will be;

[tex]\rm F_1 = 2 \times cos 45^0 \\\\ \rm F_1 =1.41 \ N[/tex]

For both the charge the net force is the double the force due to the one charge;

[tex]\rm F = 2 \times F_1 \\\\ \rm F = 2 \times 1.41 \\\\ F=2.82 \ N[/tex]

The magnitude of the net force that acts on the center charge will be 2.82 N.

Hence option B is correct.

To learn more about the charge refer to the link;

https://brainly.com/question/24391667