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Students in a class were surveyed about the number of children in their families. the results of the survey are shown in the table. a 2-column table has 5 rows. the first column is labeled number of children in family with entries 1, 2, 3, 4, 5 or more. the second column is labeled number of surveys with entries 9, 18, 22, 8, 3. two surveys are chosen at random from the group of surveys. after the first survey is chosen, it is returned to the stack and can be chosen a second time. what is the probability that the first survey chosen indicates four children in the family and the second survey indicates one child in the family? startfraction 1 over 50 endfraction startfraction 2 over 15 endfraction startfraction 3 over 20 endfraction startfraction 17 over 60 endfraction

Respuesta :

The probability that the first survey chosen indicates four children in the family, and the second survey indicates one child in the family is 1/5.

What is probability?

The surveys are chosen with replacement (the first one is replaced before the second is chosen), and the events are independent.  

This means that the probability of both together is the product of each event's probability.

The probability of choosing a survey that indicates 4 children in the family is 8/60 since there are 8 surveys with 4 children out of a total of (9+18+22+8+3) = 60 surveys.

The probability of choosing a survey that indicates 1 child is 9/60 since there are 9 surveys with 1 child out of a total of 60.

Together this gives us;

[tex]= \dfrac{8}{60} \times \dfrac{9}{60}\\\\ =\dfrac{ 72}{360} \\\\ =\dfrac{1}{5}[/tex]

Hence, the probability that the first survey chosen indicates four children in the family, and the second survey indicates one child in the family is 1/5.

To know more about probability click the link given below.

https://brainly.com/question/13379260

shaunmowen45

Answer:

1/50

Step-by-step explanation:

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