PLEASE HELP Evan earned a score of 610 on Exam A that had a mean of 650 and a standard deviation of 40. He is about to take Exam B that has a mean of 600 and a standard deviation of 50. How well must Evan score on Exam B in order to do equivalently well as he did on Exam A? Assume that scores on each exam are normally distributed.

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Using z-scores, it is found that he must score 550 on Exam B order to do equivalently well as he did on Exam A.

What is the z-score formula?

The z-score of a measure X of a distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The z-score measures how many standard deviations the measure is above or below the mean.

For Exam A, we have that the parameters are [tex]X = 610, \mu = 650, \sigma = 40[/tex], hence his grade had a z-score given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{610 - 650}{40}[/tex]

[tex]Z = -1[/tex]

In Exam B, with [tex]\mu = 600, \sigma = 50[/tex], we want the grade X with the same z-score of Z = -1, hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-1 = \frac{X - 600}{50}[/tex]

X - 600 = -50

X = 550.

He must score 550 on Exam B order to do equivalently well as he did on Exam A.

More can be learned about z-scores at https://brainly.com/question/24663213