The simplest form of a^2-ab is given by 3x^3 + x^2 + 6x - 9.
We have given that,
a = x^2,
b = 3x + 2,
c = x – 3
We have to determine ab- c^2.
A fraction is in its simplest form when the numerator and the denominator have no common factors besides one.
ab- c^2
[tex]=x^2(3x+2) - (x-3)^2\\ =3x^3 + 2x^2 - (x^2 - 6x + 9) \\=3x^3 + 2x^2 - x^2 + 6x - 9 \\=3x^3 + x^2 + 6x - 9\\[/tex]
The simplest form of a^2-ab is given by 3x^3 + x^2 + 6x - 9.
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