The center of the circle x² + y² + 8x − 6y + 21 = 0 is at (-4, 3) and the radius of the circle is 2 units.
It is a locus of a point drawn an equidistant from the center. The distance from the center to the circumference is called the radius of the circle.
The equation of the circle is given as
x² + y² + 8x − 6y + 21 = 0
The equation can be written as
x² + 8x + 16 + y² − 6y 9 = 4
(x + 4)² + (y − 3)² = 2²
Then the center of the circle is at (-4, 3) and the radius of the circle is 2 units.
More about the circle link is given below.
https://brainly.com/question/11833983
