What is the equation of the line that passes
through the point (-2,2) and the point (-6,4)?

Answer:
y = -1/2x+1
Step-by-step explanation:
First step is to find the slope
m = (y2-y1)/(x2-x1)
= ( 4-2)/(-6 - -2)
(4-2)/(-6+2)
2/-4
-1/2
Then we can use the slope intercept form of a line
y = mx+b where m is the slope and b is the y intercept
y = -1/2x+b
Substitute a point into the equation to find b
2 = -1/2(-2) +b
2 = 1+b
Subtract 1 from each side
1 =b
y = -1/2x+1
y = mx + b
Where m = slope and b is the y intercept
Let's find the slope = change in y/change in x
m = (4-2)/(-6+2) = 2/-4 = -1/2
Now we have:
y = (-1/2)x + b
Now substitute point (-6,4)
4 = (-1/2)(-6) + b
4 = 3 + b
b = 1
So y = (-1/2)x + 1 is the equation
ANSWER:
[tex]y=(-\frac{1}{2})x[/tex]+1
so letter c