Sphere B is the image of sphere A after dilation by a scale factor of 44. If the surface area of sphere B is 432 km^2, find the surface area of sphere A, the preimage.

27 km²
[tex]SA=4\pi Jr^2[/tex]
[tex]4\pi r^2_B=432[/tex]
[tex]r^2_B=\frac{108}{\pi}[/tex]
[tex]r_B=\frac{6\sqrt3}{\sqrt{50}}[/tex]
[tex]r_A=\frac{r_B}{4}=\frac{3\sqrt3}{2\sqrt\pi}[/tex]
[tex]S_0SA=4\pi Y\begin{matrix}2\\A\\\end{matrix}[/tex]
[tex]=4\pi\bullet\frac{27}{4\pi}[/tex]
[tex]=27\ km[/tex]
[tex]Y_B:Y_A=4=1[/tex]
[tex]SA_B:SA_A=16:1[/tex]
[tex]432\div 16=27\ km^2[/tex]
[tex]simple\ relation.[/tex]
I hope this helps you
:)