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A cyclist bikes with an average velocity of 20 m/s for 5 seconds.

What is the magnitude of the cyclist's displacement?
Your answer should have one significant figure.

Respuesta :

Annder

Explanation:

v = s/t

20 = s/5

100 = s

s = 100 = 1 × 10².

When a cyclist bikes with an average velocity of 20 m/s for 5 seconds, the magnitude of the cyclist displacement would be 1×10² meters.

What is Velocity?

The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object. The unit of velocity is meter/second. It can also be represented by the infinitesimal rate of change of displacement with respect to time. The generally considered unit for velocity is a meter per second.

The mathematical expression for velocity is given by the formula

velocity= total displacement/Total time

The area under the velocity-time graph represents the total displacement covered by the object while the slope of the velocity time graph represents the acceleration of the object.

For the given problem when a cyclist bikes with an average velocity of 20 m/s for 5 seconds,

Displacement =velocity×time

                       =20×5

                       =1×10²

The magnitude of the cyclist's displacement is 1×10²

Learn more about Velocity from here

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