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What is the volume, in liters, of 13.5 moles of a gas at STP? (STP = 273.15K, 1 atmosphere)


P
V
=
n
R
T

R = 0.0821
a
t
m
⋅
L
m
o
l
⋅
K

Respuesta :

40042

Answer:

302.75 Liters

Explanation:

Given:

P = 1 atm

V = ?

n = 13.5 moles

R = 0.0821 atm x L / mole x K

T = 273.15 K

PV = nRT

(1) (V) = (13.5) (0.0821) (273.15)

V = 302.75 Liters

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