Answer:
[tex]y=-4,\:x=\frac{14}{5}[/tex]
Step-by-step explanation:
[tex]\begin{bmatrix}-3y+5x=26\\ -2-5x=-16\end{bmatrix}[/tex]
Isolate x for -2-5x=-16:
[tex]x=\frac{14}{5}[/tex]
[tex]\mathrm{Substitute\:}x=\frac{14}{5}[/tex]
[tex]\begin{bmatrix}-3y+5\cdot \frac{14}{5}=26\end{bmatrix}[/tex]
[tex]Simplify[/tex]
[tex]\begin{bmatrix}-3y+14=26\end{bmatrix}[/tex]
Isolate y for -3y+14=26:
[tex]y=-4[/tex]
[tex]\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}[/tex]
[tex]y=-4,\:x=\frac{14}{5}[/tex]
