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A spring gun shoots out a plastic ball at speed v0. The spring is then compressed twice the distance it was on the first shot

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Based on the compression of the spring and the speed, the following are true:

  • The factor by which the spring's potential energy is increased is = 4.
  • The factor of increase in speed = 2.

What is the factor of increase in potential energy?

Potential energy is found as:

= 0.5k x (2 x compression²)

= 4 x 1/2kx²

The 4 shows that the potential energy increases by 4 times.

What is the factor of increase in speed?

Initial speed is:

= x × √(k/m)

New speed will be:

= Compression factor x speed

= 2x × √(k/m)

The speed will therefore be increased by a factor of 2.

Find out more on potential energy at https://brainly.com/question/14427111.

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