Answer:
[tex]\sf\boxed{ \sf \dfrac{1}{2} \ is \ the\ slope }[/tex]
If lines are parallel or tangent, the slope remains same.
[tex]\sf \large\boxed{\sf m_1 \rightarrow m_2}[/tex]
If lines are perpendicular or normal, the slope becomes negatively inverse
[tex]\sf \large\boxed{\sf m_1 \rightarrow -(\frac{1}{m_2} )}[/tex]
With this Here the line a is perpendicular to line b,
therefore using formula: [tex]\sf \large {-(\dfrac{1}{-2} )} \rightarrow \dfrac{1}{2}[/tex]
For more briefings on parallel and perpendicular lines:
brainly.com/question/12076533
