[tex]~~~~~~ \textit{Compound Interest Earned Amount}[/tex]
[tex]A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$2500\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years\dotfill &3 \end{cases} \\\\\\ A=2500\left(1+\frac{0.04}{12}\right)^{12\cdot 3}\implies A=2500\left( \frac{301}{300} \right)^{36}\implies A\approx 2818.18[/tex]
