The expected frequencies from the data conducted to investigate the differences in the length of stay of a trip will be 221.7097, 72.471, 49.3881, and 25.7677.
From the complete question, the expected frequencies from the data about the trip will be calculated thus:
E(240) = (379 × 413) ÷ 706
=221.7097
E(83) =(379 × 153) ÷ 706
=72.471
E(40) = (379 × 92) ÷ 706
=49.3881
E(16) =(379 × 48) ÷ 706
=25.7677
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