About 1407 sharks would be needed to have a margin of error of 0.25
Margin of error is used to determine by what value there is deviation from the real value. Margin of error (E) is given by:
[tex]E=Z_\frac{\alpha}{2} *\frac{standard\ deviation}{\sqrt{sample\ size} }[/tex]
The 90% confidence level have a z score of 1.645. Hence for E = 0.25, standard deviation = 5.7 feet, hence:
[tex]0.25=1.645*\frac{5.7}{\sqrt{sample\ size}}\\ \\sample\ size=1407[/tex]
About 1407 sharks would be needed to have a margin of error of 0.25
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