Using the uniform distribution, it is found that the variance of x is of 2.0833.
It is a distribution with two bounds, a and b, in which each outcome is equally as likely.
The variance is given by:
[tex]V(X) = \frac{(b - a)^2}{12}[/tex]
In the die, all outcomes between 1 and 6 are equally as likely, hence the bounds are a = 1, b = 6, and the variance is given by:
[tex]V(X) = \frac{(6 - 1)^2}{12} = 2.0833[/tex]
More can be learned about the uniform distribution at https://brainly.com/question/13889040
