Which equation represents the general form a circle with a center at (–2, –3) and a diameter of 8 units? x2 y2 4x 6y – 51 = 0 x² y² – 4x – 6y – 51 = 0 x2 y2 4x 6y – 3 = 0 x2 y2 – 4x – 6y – 3 = 0.

Respuesta :

The equation represents the general form a circle with a center at

(–2, –3) and a diameter of 8 units is,

[tex]x^{2} +4x+y^{2} +6y-3=0[/tex]

Given that,circle with a center at (–2, –3)

diameter of circle is  8 units

To find

the equation of the circle that represents the general form of a circle with a center at (–2, –3) and a diameter of 8 units.

Radius of the Circle is,

The diameter of the circle is 8 units. therefore,

[tex]radius=\frac{d}{2}=\frac{8}{2} =4[/tex]

Equation of a circle

The equation of the circle that represents the general form of a circle with a center at (–2, –3) and a radius of 4 units.

What is the general form of equation of circle?

[tex](x-h)^{2} +(y-k)^{2} =R^{2}[/tex]

Substituting the values,

[tex](x-(-2))^{2} + (y-(-3))^{2} =4^{2}[/tex]

[tex](x+2)^{2} + (y+3)^{2} =4^{2}\\[/tex]

[tex]x^{2} +4x+4+y^{2} +6y+9=0[/tex]

[tex]x^{2} +4x+y^{2} +6y-3=0[/tex]

Therefore, the option C is correct.

The equation represents the general form a circle with a center at

(–2, –3) and a diameter of 8 units is

[tex]x^{2} +4x+y^{2} +6y-3=0[/tex]

To learn more about the general form of circle visit:

https://brainly.com/question/3612143