By analysing graph and then checking for all options we got that graph represent the function F(x) = -3(x +1)^2+ 2
Function is a relation from one set to another with a property that every element of a first set has a unique image in second set.
Here by looking at graph we can say that graph is if a quadratic equation
and it passes through (0,-1) and also from (-1,2)
Now we will check all options
(1)
Given function is
[tex]F(x) = 3(x +1)^2+ 2[/tex]
Put x=0
[tex]F(0) = 3(0+1)^2+ 2=3+2=5[/tex]
This function not passes through point (0,-1)
(2)
Given function is
[tex]F(x) = -3(x +1)^2+ 2[/tex]
Put x=0
[tex]F(0) = -3(0+1)^2+ 2=-3+2=-1[/tex]
Put x= -1
[tex]F(-1) = -3(-1 +1)^2+ 2=0+2=2[/tex]
This function passes through both points (0,-1) and (-1,2)
(3)
Given function is
[tex]F(x) = -3(x +1)^2- 2[/tex]
Put x= -1
[tex]F(-1) = -3(-1 +1)^2-2=0-2=-2[/tex]
This function not passes through point (-1,2)
(4)
Given function is
[tex]F(x) = 3(x +1)^2+ 2[/tex]
Put x=0
[tex]F(0) = 3(0+1)^2+ 2=3+2=5[/tex]
This function not passes through point (0,-1)
By analysing graph and then checking for all options we got that graph represent the function F(x) = -3(x +1)^2+ 2
To learn more about function visit : https://brainly.com/question/25638609
Hi,
The correct answer is f(x) = -3(x + 1)^2 + 2.
f(x) = 3(x + 1)^2 + 2: is graphed blue
f(x) = -3(x + 1)^2 + 2: is graphed purple
f(x) = -3(x + 1)^2 - 2: is graphed red
f(x) = 3(x - 1)^2 + 2: is graphed green
As the graph shows, the correct one is Purple.
XD
