A balloon with a negative charge of -2.0×10-8 C is held 2 cm (0.02 m) below a rod with a positive charge of 2.0×10-8 C. What is the force between the balloon and the rod?

Respuesta :

The force of attraction between the balloon and the rod is 9 x 10⁻³ N.

Force of attraction between the balloon and the rod

The force of attraction between the balloon and the rod is calculated by applying Coulomb's law as shown below;

[tex]F = \frac{kq_1 q_2}{r^2}[/tex]

where;

  • r is the distance between the charges
  • k is Coulomb's constant = 9 x 10⁹ Nm²/C²

F = (9 x 10⁹) x (2.0 x 10⁻⁸)²/(0.02)²

F = 9 x 10⁻³ N

Thus, the force of attraction between the balloon and the rod is 9 x 10⁻³ N.

Learn more about Coulomb's force here: https://brainly.com/question/24743340