Answer:
no solutions exist
Step-by-step explanation:
You can rewrite the denominator as:
-2(2x-6) so the equation becomes:
[tex]-\frac12 \cdot \frac{2x-6}{2x-6} > 0[/tex]
from which you can see that not only should x ≠ 3, but for all values of x≠3 the equation is false.
