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The half-life of gold-195m is approximately 30.5 seconds.
Step 2 of 3: How much of a 12 gram sample of gold-195m would remain after 41 seconds? Round to three decimal places.

Respuesta :

Eduard22sly

The amount of the 12 grams sample of gold-195m having a half-life of 30.5 s that would remain after 41 s is 4.726 g

How to determine the number of half-lives

  • Half-life (t½) = 30.5 s
  • Time (t) = 41 s
  • Number of half-lives (n) =?

n = t / t½

n = 41 / 30.5

n = 82/61

How to determine the amount remaining

  • Original amount (N₀) = 12 g
  • Number of half-lives (n) = 82/61
  • Amount remaining (N) =?

N = N₀ / 2ⁿ

N = 12 / 2^(82/61)

N = 4.726 g

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