A sample of 92 mL hydrogen gas at 602 °C, when cooled to 83 °C at constant pressure, the gas will occupy a volume of 0.0374 liters.
We can calculate the volume of the gas with the Ideal gas law:
[tex] PV = nRT [/tex]
Where:
Initially, we have:
[tex] \frac{nR}{P} = \frac{V_{i}}{T_{i}} [/tex]
Where:
[tex]\frac{nR}{P} = \frac{V_{i}}{T_{i}} = \frac{0.092 L}{875 K} = 1.05 \cdot 10^{-4} L/K[/tex]
When the gas is cooled to 83 °C (356 K), the pressure is constant and the number of moles is the same, so the volume is:
[tex]V_{f} = \frac{nR}{P}T_{f} = 1.05 \cdot 10^{-4} L/K*356 K = 0.0374 L[/tex]
Therefore, the hydrogen gas will occupy 0.0374 liters when is cooled to 83 °C.
Find more about Ideal gas law here:
brainly.com/question/4147359
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