One 23.5 fl. oz. (695 mL) can of American malt liquor, which is 12 % (v/v) in ethanol, contains 83.4 mL of ethanol.
It represents the milliliters of a solute in 100 milliliters of solution.
We have the following information:
695 mL Solution × (12 mL Ethanol/100 mL Solution) = 83.4 mL Ethanol
One 23.5 fl. oz. (695 mL) can of American malt liquor, which is 12 % (v/v) in ethanol, contains 83.4 mL of ethanol.
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