Answer:
4.15g
Explanation:
Balance the reaction:
2Mg + O2 = 2MgO
Find limiting reactant from the two, by dividing miles with coefficient
2.5/24.3 = 0.103 moles/2 = 0.0515
5/16 = 0.31 moles/2 = 0.156
0.0515 is small than 0.156, so limiting reactant is Mg
Compare the ratio of Mg with MgO
Ratio is 2:2
So same moles = 0.103 moles
Mass = moles x molar mass of MgO
Mass = 0.103 x 40.3
= 4.15g
*please give brainlest*
