Help me with this please?

Answer:
[tex]\sqrt{51}[/tex] or 7.14
Step-by-step explanation:
Using the Pythagoras theorem, we can conclude the formula that we are going to use here is [tex]a^{2}+b^{2} = c^{2}[/tex]
As we can see, this is a right triangle given that it has the square in the corner there. With this information, we can conclude that the longest side is 10, making it the hypotenuse or [tex]c[/tex]
Now we need to find [tex]b[/tex] in the formula of [tex]a^{2}+b^{2} = c^{2}[/tex] making the equation [tex]b^{2} = c^{2} - a^{2}[/tex] or [tex]b = \sqrt{ c^{2} - a^{2}}[/tex]
Given the provided information, this would be [tex]b^{2} = 10^{2} - 7^{2}[/tex] or [tex]b = \sqrt{ 10^{2} - 7^{2}}[/tex]
Simplifying it would be [tex]b = \sqrt{ 100-49[/tex] = [tex]\sqrt{51}[/tex]
The radical form would be [tex]\sqrt{51}[/tex]
While it's integer would be 7.14
Hope this helps!
Answer:
Step-by-step explanation:
Use Pythagorean theorem,
Let the third side =x
base² + altitude² = hypotenuse²
7² + x² = 10²
49 + x² = 100
x² = 100 - 49
x² = 51
x = √51