Answer:
[tex]x=2\sqrt{5}[/tex]
Step-by-step explanation:
If that is a square, then all sides are the same. Therefore, it's a [tex]\sqrt{10}[/tex] by [tex]\sqrt{10}[/tex] shape. We'll use Pythagorean Theorem to find the diagonal.
[tex]a^2+b^2=c^2\\\sqrt{10}^2+ \sqrt{10}^2=x^2\\10+10=x^2\\20=x^2\\\sqrt{20}=x\\\sqrt{4*5}=x\\ 2\sqrt{5}=x[/tex]
Since it's not a fraction, there is no denominator to rationalize. Let me know if you have any other questions!
