shreyasingh85
contestada

Multiply: x^2×y^2 × mn / x^11
y^12 m²n² × x^8y^9 mn /ab
[tex]multiply : \frac{ {x}^{2} \times {y}^{2} \times mn}{ {x}^{11} {y}^{12} {m}^{2} {n}^{2} } \times \frac{ {x}^{8} {y}^{9} mn}{ab} \\ [/tex]
​

Respuesta :

KillowPeak

Answer:

Answer: |

1/(a b x y)

Step-by-step explanation:

Simplify the following:

(x^2 y^2 m n x^8 y^9 m n)/(x^11 y^12 m^2 n^2 a b)

Combine powers. (m n x^8 y^9 m n x^2 y^2)/(a b m^2 n^2 x^11 y^12) = (m^(1 + 1 - 2) n^(1 + 1 - 2) x^(8 + 2 - 11) y^(9 + 2 - 12))/(a b):

(m^(1 + 1 - 2) n^(1 + 1 - 2) x^(8 + 2 - 11) y^(9 + 2 - 12))/(a b)

1 + 1 - 2 = 0:

(m^0 n^(1 + 1 - 2) x^(8 + 2 - 11) y^(9 + 2 - 12))/(a b)

1 + 1 - 2 = 0:

(m^0 n^0 x^(8 + 2 - 11) y^(9 + 2 - 12))/(a b)

8 + 2 - 11 = -1:

(m^0 n^0 x^(-1) y^(9 + 2 - 12))/(a b)

9 + 2 - 12 = -1:

(m^0 n^0 y^(-1))/(x a b)

n^0 = 1:

m^0/(a b x y)

m^0 = 1:

Otras preguntas