Graph the functions below. Arrange the parabolas with respect to the position of their vertices from left to right.
y=F(4x+3)
y=F(x-3)
y=F(2x-1)
y=F(x/2-2
y=F(x-7)
y=F(x+3) /3
y=F(x-2)

Respuesta :

Answer:

6  1  3  7  2  4  5

Step-by-step explanation:

Let us initially consider that the vertex of F(x) is (0,0).

1: now for y=F(4x+3)

the vertex is [tex]\frac{-3}{4}[/tex].

2: for y=F(x-3)

the vertex is 3.

3: for y=F(2x-1)

the vertex is [tex]\frac{1}{2}[/tex].

4: for y=F(x/2-2)

the vertex is 4.

5: for y=F(x-7)

the vertex is 7.

6: for y=F(x+3)/3

the vertex is -3.

7: for y=F(x-2)

the vertex is 2.

Hence on arranging based on the vertex from left to right we get that it is arranged as:

6  1  3  7  2  4  5



Answer:

Make sure to read question and answers carefully bc it might be a bit different

Step-by-step explanation:

I got it right on PLATO/edmentum

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