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Pulling a wheel with a string? A bicycle wheel is mounted on a fixed, frictionless axle, with a light string wound around its rim. The wheel has moment of inertia I = k m r^2, where m is its mass, r is its radius, and k is a dimensionless constant between zero and one. The wheel is rotating counterclockwise with angular velocity omega_0, when at...

Respuesta :

a)♣ the string being pulled, 
the angular speed is: w1=w0 +w’*t, hence t=(w1-w0)/w’; 
the angular path is: b=w0*t+0.5*w’*t^2, where angular acceleration 
w’=T/J, torq T=F*r, and b*r=L; 
♦ thus b=w0*(w1-w0)/w’ +0.5*w’*((w1-w0)/w’)^2 = 
= (w1-w0)*(w0 +0.5w1 -0.5w0)/w’ =0.5*(w1^2 –w0^2)/w’; 
♠ and b=L/r =0.5*(w1^2 –w0^2)/(F*r/J); 
2(F*r/J)*L/r =w1^2 –w0^2, hence 
w1^2=2F*L/J +w0^2; 
b)♣ the power is P=F*(w0*r);

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