Two groups of people entered a Drive-In restaurant. The first group ordered 6
hamburgers and 5 orders of French fries, and paid $4.55. The second group ordered 10
hamburgers and 6 orders of French fries and paid $7.00. How much would you have to
pay for one hamburger and one order of French fries?
So here is how we are going to answer the problem above: Given that f is the cost of French fries and b is the cost of Hamburger. So: 5f + 6b = 4.55 5f = 4.55 - 6b (multiply both sides by 6) and we get 30f = 27.3 - 36b
Next, 6f + 10b = 7.00 (multiply both sides by 5) and we get 30f + 50b = 35 (Now substitute the value of 30f) 27.3 - 36b + 50b = 35 14b = 35 - 27.3 14b = 7.7 (divide both sides by 14) b = 0.55
Therefore, the cost per hamburger is $0.55
Now go back to the cost of fries: 30f = 27.3 - 36b 30f = 27.3 - 36(0.55) 30f = 27.3 - 19.8 30f = 7.5 (divide both sides by 30) f = 0.25 Therefore, the cost per french fries is $0.25 Hope this helps.
