contestada

The Handbook of Chemistry and Physics lists the density of a certain liquid to be 0.7988 g/mL. Kelvin experimentally finds this liquid to have a density of 0.7925 g/mL. The teacher allows up to +/- 0.500% error to make an ""A"" on the lab. Did Kelvin make an ""A""? Prove your answer.

Respuesta :

LammettHash

0.500% of 0.7988 is

0.005 • 0.7988 = 0.003994

The absolute difference between Kelvin's measurement has to be within this threshold. The absolute difference between what he found and what's worth an A is

|0.7925 - 0.7988| = 0.0063

but this is larger than 0.003994. So Kelvin did not make an "A".

Otras preguntas