There are 8 terms in the expansion of [tex](3y^2 - 4z)^7[/tex]
The binomial expression is given as:
[tex](3y^2 - 4z)^7[/tex]
The number (n) of terms in a binomial expansion that has a power of m is
[tex]n = m + 1[/tex]
The degree of the expression [tex](3y^2 - 4z)^7[/tex] is 7.
So, the number of terms is calculated as follows
[tex]n =7 + 1[/tex]
Add 7 and 1
[tex]n =8[/tex]
Hence, there are 8 terms in the expansion of [tex](3y^2 - 4z)^7[/tex]
Read more about binomial expansion at:
https://brainly.com/question/13602562
