Answer:
-20 and two nonreal solutions.
Step-by-step explanation:
The discriminant of a quadratic equation uses the equation:
[tex]b^2 - 4ac[/tex]
Where the value of this calculation can tell you what solutions there are, plug known values in:
[tex]x^2 + 6x + 14 = 0\\a = 1\\b = 6\\c = 14\\[/tex]
[tex]b^2 - 4ac\\6^2 - 4(1)(14)\\36 - (4 * 14)\\36 - 56 = -20[/tex]
As -20 < 0, this means that there is not a real solution, resulting in the first option being correct.
Hope this helps!
