Answer:
The burgers cost $2.50 and the cookies cost $1.25.
Step-by-step explanation:
Let b represent burgers and c represent cookies.
2b + 2c = 7.50
4b + 3c = 13.75
Step 1: Use one of the two equations and isolate one of the variables.
2b + 2c = 7.50
- 2c -2c
[tex]\frac{2}{2}[/tex]b = [tex]\frac{7.50}{2}[/tex] - [tex]\frac{2}{2}[/tex]c
b = 3.75 - c
Step 2: Plug what you get for b into the second equation.
4(3.75 - c) + 3c = 13.75
15 - 4c + 3c = 13.75
15 - 1c = 13.75
Step 3: Isolate the variable and solve for c.
15 - 1c = 13.75
-15 -15
[tex]-\frac{1}{1}[/tex]c = [tex]\frac{-1.25}{-1}[/tex]
c = 1.25 ← price for cookies
Step 4: Plug in what you have for c into one of the previous equations and solve for b.
2b + 2(1.25) = 7.50
2b + 2.50 = 7.50
- 2.50 -2.50
[tex]\frac{2}{2}[/tex]b = [tex]\frac{5}{2}[/tex]
b = 2.50 ← price for burgers
Now you know the cost of each item:
The burgers cost $2.50 and the cookies cost $1.25.
