Decimal notation is a way of expressing a number in base ten but with a decimal part. Therefore, from the given question;
Number bases is a method of expressing numbers in different notations with respect to the required base. When given numbers in base ten, it is required to divide it by the number base for conversion using long division method so as to convert it to any required base. So converting each element in the given set to base 5, we have:
{1000, 1001, 1002, 1003, 1004,......, 2000}
So that:
i. 1000 converted to base 5, we have:
5 1000
5 200 r 0
5 40 r 0
5 08 r 0
5 01 r 3
00 r 1
⇒ [tex]13000_{5}[/tex]
ii. 1001 converted to base 5, we have:
5 1001
5 200 r 1
5 40 r 0
5 08 r 0
5 01 r 3
00 r 1
⇒ [tex]13001_{5}[/tex]
iii. 1002 converted to base 5, we have:
5 1002
5 200 r 2
5 40 r 0
5 08 r 0
5 01 r 3
00 r 1
⇒ [tex]13002_{5}[/tex]
So then, the set in base 5 is:
{13000, 13001, 13002, 13003, 13004,......, 31000}
To determine the number whose digits have the least sum;
a. 13000 = 1 + 3 + 0 + 0 + 0 = 4
b. 13001 = 1 + 3 + 0 + 0 + 1 = 5
c. 13002 = 1 + 3 + 0 + 0 + 2 = 6
d. 13003 = 1 + 3 + 0 + 0 + 3 = 7
e. 13004 = 1 + 3 + 0 + 0 + 4 = 8
. . . . . . .
. . . . . . .
z. 31000 = 3 + 1 + 0 + 0 + 0 = 4
Thus it would be observed that in base five, 1000, 1500 and 2000 digits gave the least sum of 4, so then:
[tex]\frac{1000+1500+2000}{3}[/tex] = 1500
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