Answer:
[tex]\boxed {\boxed {\sf y= -3x+5}}[/tex]
Step-by-step explanation:
We are asked to find the equation of the line that passes through the point (2, -1) and has a slope of -3.
We are given a point and the slope, so we can use the point-slope formula.
[tex]y-y_1=m(x-x_1)[/tex]
In this formula, m is the slope and (x₁, y₁) is the point the line passes through.
The line has a slope of -3 and passes through (2, -1).
Substitute the values into the formula.
[tex]y--1= -3 (x-2)[/tex]
[tex]y+1= -3 (x-2)[/tex]
Distribute the -3 on the right side. Multiply each term inside the parentheses by -3.
[tex]y+1 = (-3*x) + (-3*-2)[/tex]
[tex]y+1=(-3x) + (6)[/tex]
[tex]y+1=-3x+6[/tex]
Subtract 1 from both sides of the equation to isolate the variable y.
[tex]y+1-1=-3x+6-1[/tex]
[tex]y=-3x +5[/tex]
The equation of the line is y= -3x+5.
