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Violet light has a wavelength from 380 nm to 420 nm.
What velocity must a free electron have in order to exhibit the same wavelength as a violet photon with a
wavelength of 415 nm?

Respuesta :

This question involves the concepts of de Broglie's wavelength and momentum.

The velocity of the electron must be "1754.27 m/s".

de Broglie's wavelength is a wavelength associated with a moving matter particle. It is connected to the momentum of the particle by the following formula:

[tex]P =\frac{h}{\lambda}\\\\mv=\frac{h}{\lambda}\\\\v=\frac{h}{m\lambda}\\\\[/tex]

where,

v = velocity of electron = ?

h = Plamk's Constant = 6.625 x 10⁻³⁴ J.s

m = mass of electron = 9.1 x 10⁻³¹ kg

λ = de Broglie's wavelength = 415 nm = 4.15 x 10⁻⁷ m

Therefrore,

[tex]v=\frac{6.625\ x\ 10^{-34}\ J.s}{(9.1\ x\ 10^{-31}\ kg)(4.15\ x\ 10^{-7}\ m)}[/tex]

v = 1754.27 m/s

Learn more about de Broglie's wavelength here:

https://brainly.com/question/20339737?referrer=searchResults

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