The tension on the connecting string of the two blocks is 6 N.
The given parameters;
- coefficient of friction between the surface and larger block, μ₁ = 0.20
- coefficient of kinetic friction between the surface and smaller block, μ₂ = 0.3
- the horizontal force, F = 10 N
- mass of the larger block, m₁ = 2M = 2 kg
- mass of the smaller block, m₂ = M = 1 kg
The net force on the block along the horizontal is calculated as follows;
[tex]F + \mu_2Mg - \mu_1 (2M)g = a(M+2M)\\\\10 \ + \ 0.3\times 1\times 9.8 \ - \ 0.2\times 2\times 9.8 = 3a\\\\9.02 = 3a\\\\a = \frac{9.02}{3} \\\\a = 3 \ m/s^2[/tex]
The tension on the connecting string is calculated as follows;
T = m₁a
T = (2M)a
T = 2 x 3
T = 6 N
Thus, the tension on the connecting string of the two blocks is 6 N.
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