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crissz67

Answer:

The line are perpendicular

Step-by-step explanation:

when two lines are parallel m1= m2(slopes are equal) ;while m1 = -1/m2 when they are perpendicular. m1 = (using the formula y=mx + c) y = -2x +6; m1 = -2 ; m2 ( using y = mx +c) ; 2y = x - 4 ( divide both sides by 2) y = 1/2x -2 ; m2 =1/2 ; 1/2 is not equal to -2 but 1/2 = -1/-2 so it is perpendicular

djtwinx017
2x + y = + 6
x - 2y = 4

Transform both equations into slope-intercept form, y = mx + b:

2x + y = 6
Subtract 2x from both sides
2x - 2x + y = -2x + 6
y = -2x + 6. (EQUATION 1)


x - 2y = 4
Subtract x from both sides

x - x - 2y = - x + 4
-2y = -x + 4
Divide both sides by -2:
-2y/-2 = (-x + 4)/-2

y = 1/2x - 4 (EQUATION 2)

Now that we have both equations in slope-intercept form, it is easier to determine whether they are perpendicular from each other.

Perpendicular lines have negative reciprocal slopes—that is, if you multiply both slopes, the product will = -1.

The slope of Equation 1 is -2, which is a negative reciprocal of the slope of Equation 2, which is 1/2. Therefore, both lines are PERPENDICULAR from each other.

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