⇒ Given:
Inner radius of the cylindrical pipe = 5 cm
Outer radius of the cylindrical pipe = 5.5 cm
In this question, we have to find the area of the cross section of the cylindrical pipe.
Let the inner radius be r and the outer radius be R.
Formula to be used :
[tex]\pi {r}^{2} - \pi {r}^{2} [/tex]
→ Taking out the common terms:
[tex]\pi ( {r}^{2} - {r}^{2} )[/tex]
Hence the required area is :
[tex]\pi ( {r}^{2} - {r}^{2} )[/tex]
Now,
r = 5 cm
R = 5.5 cm
Substituting the values in the equation:
[tex]\pi ( {5.5}^{2} - {5}^{2} ) \\ [/tex]
Giving the value of π as 3.14:
[tex]3.14(30.25 - 25) \\ 3.14 \times 5.25 \\ {16.485}^{2} [/tex]
[tex]hence the area of \\ cross- section of the cylinder \\ pipe \: is \: {16.485}^{2} [/tex]
