The normal force is 161 N, the coefficient of friction is 0.62 and the acceleration is 11.68 m/s^2.
Given that;
Fa = Ff + mgsinθ
Where; Ff =μk FN
Fa = μk FN + mgsinθ
But FN = mgcosθ
Fa = μk mgcosθ + mgsinθ
Since the normal force = mgcosθ, we have;
FN = 25 kg × 10 × cos(50°)
FN = 161 N
For the coefficient of friction;
Ff = μkFN
μk = Ff/FN
μk = 100N/161 N
μk = 0.62
To obtain the acceleration
Fa = Ff + mgsinθ
Since Ff = 100 N, then
Fa = 100 N + (25 × 10 × sin 50°)
Fa = 292 N
Since;
Fa = ma
a = Fa/m
a = 292 N/25 kg
a = 11.68 m/s^2
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