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What is an equation of the line that passes through the point (−2,1) and is parallel to the line whose equation is 4x − 2y = 8? *

Respuesta :

crissz67

Answer:

since the lines are parallel to each other

m1 = m2( their slopes are equal)

4x - 2y = 8

-2y = 8 -4x

-2y = -4x + 8

divide both sides by -2

y = 2x - 4

since y = mx + c

m = 2

using the formula

y -y1 = m(x - x1)

y - 1 = 2 (x -(-2))

y-1 =2 (x +2)

y -1 = 2x +4

y = 2x +4 +1

y= 2x + 5(equation of the line)

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