Probabilities are used to determine the chances of events.
The probability that he makes 2 of his next 3 free throws is 0.384
The given parameters are:
[tex]\mathbf{p = 80\%}[/tex] -- the proportion of free throws the player makes
[tex]\mathbf{n = 3}[/tex] --- the number of throws
[tex]\mathbf{r = 2}[/tex] --- the throws he makes
The probability is calculated as follows:
[tex]\mathbf{P(r) = ^nC_r \times p^r \times (1 - p)^{n - r}}[/tex]
Substitute known values
[tex]\mathbf{P(2) = ^3C_2 \times (80\%)^2 \times (1 - 80\%)^{3 - 2}}[/tex]
Solve each factor
[tex]\mathbf{P(2) = 3 \times 0.64 \times 0.20}[/tex]
[tex]\mathbf{P(2) = 0.384}[/tex]
Hence, the probability that he makes 2 of his next 3 free throws is 0.384
Read more about binomial probabilities at:
https://brainly.com/question/19578146
