Partial pressure is the pressure contributed by each component of a gaseous mixture
The partial pressure of the helium after the stopcock is opened is 1.52 atm.
Reason:
Question: The possible missing part of the question are
Given parameters;
Bulb 1 content = Helium
Volume = 2.0 L
Pressure = 3.8 atm
Bulb 2 content = Nitrogen
Volume = 3.0 L
Pressure = 0.95 atm
Diagram
Solution:
The total volume of the mixture, V = 2.0 L + 3.0 L = 5.0 L
3.8 The pressure of the He in final mixture, is given as follows;
According Boyle's Law, we have;
P₁·V₁ = P₂·V₂
Where;
P₁ = The initial pressure of the helium gas = 3.8 atm
P₂ = The pressure after the stopcock is opened = Required
V₁ = The initial volume of the helium bulb = 2.0 L
V₂ = The volume of the helium after the bulb is opened = 5.0 L
Therefore;
[tex]P_2 = \dfrac{P_1 \cdot V_1}{V_2}[/tex]
Therefore;
[tex]P_2 = \dfrac{3.8 \times 2.0}{5.0} = 1.52[/tex]
The partial pressure of the helium after the stopcock is opened, P₂ = 1.52 atm.
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