Answer:
since the equation of the line passing through the given point is perpendicular to the given line(m2= -1/m1)
using the formula y=mx+c
y=2/3x +1
m1=2/3
m2= -1/2/3
m2= -3/2
the slope of the second line is -3/2 and it passes through the point(3,-2)
using the formula y-y1 = m(x-x1)
y-(-2)= -3/2(x-3)
y+2= -3/2(x-3)
multiply both sides by 2
2(y+2) = -3(x-3)
2y+4 = -3x+9
2y = -3x+5
y= -3/2x + 5/2
